C++ Certified Professional Programmer: CPP

What happens when you attempt to compile and run the following code?

#include

#include

#include

using namespace std;

int main ()

{

int t[] = {1, 2 ,3 ,4 ,5};

vectorv1(t, t+5);

listl1;

l1.assign(v1.end(), v1.begin());

for(int i=0; i

{

cout<

}

cout<

return 0;

}

A. program displays 5 4 3 2 1

B. program displays 1 2 3 4 5

C. compilation error

D. segmentation fault runtime exception

What happens when you attempt to compile and run the following code?

#include

#include

#include

#include

using namespace std;

void myfunction(int i) {

cout << " " << i;

}

bool classifier(int v) {

return v%2==0;

}

int main() {

int t[] = { 1, 5, 2, 5, 2, 4, 4, 3, 3, 1 };

vector v1(t, t+10);

set s1(t, t+10);

replace(v1.begin(), v1.end(),classifier, 10);

for_each(v1.begin(), v1.end(), myfunction);

return 0;

}

Program outputs:

A. 1 5 10 5 10 10 10 3 3 1

B. 1 5 2 5 2 4 4 3 3 1

C. compilation error

D. 10 10 2 10 2 4 4 10 10 10

What happens when you attempt to compile and run the following code?

#include

#include

#include

#include

using namespace std;

class B { int val;

public:

B(int v=0):val(v){}

int getV() const {return val;}

B operator +(const B andb )const { return B(val + b.val);} };

ostream and operator <<(ostream and out, const B and v) { out<

templatestruct Out {

ostream and out;

Out(ostream and o): out(o){}

void operator() (const T and val ) { out<

template struct Add : public binary_function {

A operator() (const A and a, const A and b) const { return a+b; }};

int main() {

int t[]={1,2,3,4,5,6,7,8,9,10};

vector v1(t, t+10);

vector v2(10);

transform(v1.begin(), v1.end(), v2.begin(), bind1st(ptr_fun (Add()), 1));

for_each(v2.rbegin(), v2.rend(), Out(cout));cout<

return 0;

}

Program outputs:

A. 1 2 3 4 5 6 7 8 9 10

B. 2 3 4 5 6 7 8 9 10 11

C. 10 9 8 7 6 5 4 3 2 1

D. 11 10 9 8 7 6 5 4 3 2

E. compilation error